1847 Tennessee gubernatorial election
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| Elections in Tennessee |
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 Government |
The 1847 Tennessee gubernatorial election was held on August 5, 1847, to elect the Governor of Tennessee. Whig nominee and former member of the Tennessee House of Representatives Neill S. Brown defeated Democratic nominee and incumbent Governor Aaron V. Brown.[1]
General election[edit]
On election day, 5 August 1847, Whig nominee Neill S. Brown won the election by a margin of 1,368 votes against his opponent Democratic nominee and incumbent Governor Aaron V. Brown, thereby gaining Whig control over the office of Governor. Brown was sworn in as the 12th Governor of Tennessee on 17 October 1847.[2]
Results[edit]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Whig | Neill S. Brown | 61,372 | 50.56 | |
| Democratic | Aaron V. Brown (incumbent) | 60,004 | 49.44 | |
| Total votes | 121,376 | 100.00 | ||
| Whig gain from Democratic | ||||
References[edit]
- ^ "Gov. Aaron Venable Brown". nga.org. Retrieved 15 February 2024.
- ^ "TN Governor". ourcampaigns.com. 7 June 2005. Retrieved 15 February 2024.
Categories:
- 1847 Tennessee elections
- Tennessee gubernatorial elections
- 1847 United States gubernatorial elections
- August 1847 events
- 1847 in Tennessee
- 1840s in Tennessee
- 1840s Tennessee elections
- 1847 elections
- 1847 elections in North America
- 1847 elections in the United States
- United States gubernatorial elections in the 1840s
- Government of Tennessee