Clapperton Island

Coordinates: 69°42′01″N 123°57′09″W / 69.70028°N 123.95250°W / 69.70028; -123.95250[1]
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69°42′01″N 123°57′09″W / 69.70028°N 123.95250°W / 69.70028; -123.95250[1]

Clapperton Island is located in the Northwest Territories, Canada, within Franklin Bay. It is 23 km (14 mi) from Cape Lyon. The island was named by John Franklin in honour of the explorer Hugh Clapperton. It is composed of limestone and is skirted by detached rocks.[2]

References[edit]

  1. ^ "Clapperton Island". Geographical Names Data Base. Natural Resources Canada.
  2. ^ Franklin, John (1828). Narrative of a Second Expedition to the Shores of The Polar Sea in the Years 1825, 1826, and 1827 (Public domain ed.). John Murray. pp. 239–. Retrieved December 29, 2012.
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