1880 Rhode Island gubernatorial election
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The 1880 Rhode Island gubernatorial election was held on April 7, 1880. Republican nominee Alfred H. Littlefield defeated Democratic nominee Horace A. Kimball with 44.82% of the vote.
General election[edit]
Candidates[edit]
Major party candidates
- Alfred H. Littlefield, Republican
- Horace A. Kimball, Democratic
Other candidates
- Albert C. Howard, Independent Republican
Results[edit]
| Party | Candidate | Votes | % | ±% | |
|---|---|---|---|---|---|
| Republican | Alfred H. Littlefield | 10,224 | 44.82% | ||
| Democratic | Horace A. Kimball | 7,440 | 32.62% | ||
| Independent Republican | Albert C. Howard | 5,047 | 22.13% | ||
| Majority | 2,784 | ||||
| Turnout | |||||
| Republican hold | Swing | ||||
References[edit]
- ^ Moore, John Leo, ed. (1994). Congressional Quarterly's Guide to U.S. elections. CQ Press. ISBN 9780871879967. Retrieved October 27, 2020.