Suchy Dwór, Pomeranian Voivodeship

Coordinates: 54°34′32″N 18°27′53″E / 54.57556°N 18.46472°E / 54.57556; 18.46472
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See also: Suchy Dwór, Lower Silesian Voivodeship
Suchy Dwór
Village
Suchy Dwór is located in Poland
Suchy Dwór
Suchy Dwór
Coordinates: 54°34′32″N 18°27′53″E / 54.57556°N 18.46472°E / 54.57556; 18.46472
Country Poland
VoivodeshipPomeranian
CountyPuck
GminaKosakowo
Population
888

Suchy Dwór [ˈsuxɨ ˈdvur] is a village in the administrative district of Gmina Kosakowo, within Puck County, Pomeranian Voivodeship, in northern Poland.[1] It lies approximately 2 kilometres (1 mi) south-west of Kosakowo, 15 km (9 mi) south of Puck, and 26 km (16 mi) north-west of the regional capital Gdańsk.

For details of the history of the region, see History of Pomerania.

References[edit]

  1. ^ "Central Statistical Office (GUS) - TERYT (National Register of Territorial Land Apportionment Journal)" (in Polish). 2008-06-01.


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