Jakopovac

Coordinates: 46°01′28″N 16°46′20″E / 46.0244343°N 16.7722427°E / 46.0244343; 16.7722427
From Wikipedia, the free encyclopedia
Jakopovac
Village
Jakopovac is located in Croatia
Jakopovac
Jakopovac
Coordinates: 46°01′28″N 16°46′20″E / 46.0244343°N 16.7722427°E / 46.0244343; 16.7722427
Country Croatia
County Bjelovar-Bilogora County
MunicipalityZrinski Topolovac
Area
 • Total1.7 sq mi (4.4 km2)
Population
 (2021)[2]
 • Total98
 • Density58/sq mi (22/km2)
Time zoneUTC+1 (CET)
 • Summer (DST)UTC+2 (CEST)

Jakopovac is a village in Croatia.

Demographics[edit]

According to the 2021 census, its population was 98.[2]

References[edit]

  1. ^ Register of spatial units of the State Geodetic Administration of the Republic of Croatia. Wikidata Q119585703.
  2. ^ a b "Population by Age and Sex, by Settlements, 2021 Census". Census of Population, Households and Dwellings in 2021. Zagreb: Croatian Bureau of Statistics. 2022.