Douglas Township, Shelby County, Iowa

Coordinates: 41°44′19″N 95°15′54″W / 41.7387°N 95.2651°W / 41.7387; -95.2651
From Wikipedia, the free encyclopedia

Douglas Township is a township in Shelby County, Iowa. There are 430 people and 11.7 people per square mile in Douglas Township. The total area is 36.7 square miles.[1]

References[edit]

  1. ^ "Census profile: Douglas township, Shelby County, IA". Census Reporter.

41°44′19″N 95°15′54″W / 41.7387°N 95.2651°W / 41.7387; -95.2651


Stub icon

This article about the geography of Shelby County, Iowa is a stub. You can help Wikipedia by expanding it.

Retrieved from "https://en.wikipedia.org/w/index.php?title=Douglas_Township,_Shelby_County,_Iowa&oldid=1177785605"