1836 South Carolina gubernatorial election
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The 1836 South Carolina gubernatorial election was held on 10 December 1836 in order to elect the Governor of South Carolina. Democratic candidate Pierce Mason Butler was elected by the South Carolina General Assembly as he ran unopposed. The exact amount of votes cast in this election is unknown.[1]
General election[edit]
On election day, 10 December 1836, Democratic candidate Pierce Mason Butler was elected by the South Carolina General Assembly, thereby retaining Democratic control over the office of Governor. Butler was sworn in as the 56th Governor of South Carolina on 17 January 1837.[2]
Results[edit]
| Party | Candidate | Votes | % | |
|---|---|---|---|---|
| Democratic | Pierce Mason Butler | 1 | 100.00% | |
| Total votes | 1 | 100.00% | ||
| Democratic hold | ||||
References[edit]
- ^ "Pierce Mason Butler". National Governors Association. Retrieved 22 May 2024.
- ^ "SC Governor". ourcampaigns.com. 23 May 2004. Retrieved 22 May 2024.
Categories:
- 1836 South Carolina elections
- South Carolina gubernatorial elections
- December 1836 events
- 1836 United States gubernatorial elections
- 1836 in South Carolina
- 1830s in South Carolina
- Indirect elections
- 1830s South Carolina elections
- 1836 elections
- 1836 elections in North America
- 1836 elections in the United States
- Single-candidate elections
- United States gubernatorial elections in the 1830s
- Government of South Carolina